YES 2.509
H-Termination proof of /home/matraf/haskell/eval_FullyBlown_Fast/empty.hs
H-Termination of the given Haskell-Program with start terms could successfully be proven:
↳ HASKELL
↳ LR
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
Lambda Reductions:
The following Lambda expression
\(m,_)→m
is transformed to
The following Lambda expression
\(_,r)→r
is transformed to
The following Lambda expression
\(q,_)→q
is transformed to
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
If Reductions:
The following If expression
if primGEqNatS x y then Succ (primDivNatS (primMinusNatS x y) (Succ y)) else Zero
is transformed to
primDivNatS0 | x y True | = Succ (primDivNatS (primMinusNatS x y) (Succ y)) |
primDivNatS0 | x y False | = Zero |
The following If expression
if primGEqNatS x y then primModNatS (primMinusNatS x y) (Succ y) else Succ x
is transformed to
primModNatS0 | x y True | = primModNatS (primMinusNatS x y) (Succ y) |
primModNatS0 | x y False | = Succ x |
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
Replaced joker patterns by fresh variables and removed binding patterns.
Binding Reductions:
The bind variable of the following binding Pattern
frac@(Double vy vz)
is replaced by the following term
Double vy vz
The bind variable of the following binding Pattern
frac@(Float ww wx)
is replaced by the following term
Float ww wx
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
Cond Reductions:
The following Function with conditions
is transformed to
undefined0 | True | = undefined |
undefined1 | | = undefined0 False |
The following Function with conditions
toEnum | 0 | = False |
toEnum | 1 | = True |
is transformed to
toEnum | xz | = toEnum3 xz |
toEnum | xy | = toEnum1 xy |
toEnum1 | xy | = toEnum0 (xy == 1) xy |
toEnum2 | True xz | = False |
toEnum2 | yu yv | = toEnum1 yv |
toEnum3 | xz | = toEnum2 (xz == 0) xz |
toEnum3 | yw | = toEnum1 yw |
The following Function with conditions
is transformed to
toEnum5 | yx | = toEnum4 (yx == 0) yx |
The following Function with conditions
toEnum | 0 | = LT |
toEnum | 1 | = EQ |
toEnum | 2 | = GT |
is transformed to
toEnum | zx | = toEnum11 zx |
toEnum | yz | = toEnum9 yz |
toEnum | yy | = toEnum7 yy |
toEnum7 | yy | = toEnum6 (yy == 2) yy |
toEnum8 | True yz | = EQ |
toEnum8 | zu zv | = toEnum7 zv |
toEnum9 | yz | = toEnum8 (yz == 1) yz |
toEnum9 | zw | = toEnum7 zw |
toEnum10 | True zx | = LT |
toEnum10 | zy zz | = toEnum9 zz |
toEnum11 | zx | = toEnum10 (zx == 0) zx |
toEnum11 | vuu | = toEnum9 vuu |
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
Let/Where Reductions:
The bindings of the following Let/Where expression
are unpacked to the following functions on top level
truncateVu6 | vuv | = properFraction vuv |
truncateM0 | vuv (m,vv) | = m |
truncateM | vuv | = truncateM0 vuv (truncateVu6 vuv) |
The bindings of the following Let/Where expression
(fromIntegral q,r :% y) |
where | |
| |
| |
| |
| |
are unpacked to the following functions on top level
properFractionR0 | vuw vux (xw,r) | = r |
properFractionQ1 | vuw vux (q,xv) | = q |
properFractionVu30 | vuw vux | = quotRem vuw vux |
properFractionR | vuw vux | = properFractionR0 vuw vux (properFractionVu30 vuw vux) |
properFractionQ | vuw vux | = properFractionQ1 vuw vux (properFractionVu30 vuw vux) |
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
mainModule Main
| ((succ :: Enum a => a -> a) :: Enum a => a -> a) |
module Main where
Num Reduction: All numbers are transformed to thier corresponding representation with Pos, Neg, Succ and Zero.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
mainModule Main
| (succ :: Enum a => a -> a) |
module Main where
Haskell To QDPs
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDPSizeChangeProof
↳ QDP
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primMinusNatS(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS(vuy390, vuy400)
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the subterm criterion [20] together with the size-change analysis [32] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs:
- new_primMinusNatS(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS(vuy390, vuy400)
The graph contains the following edges 1 > 1, 2 > 2
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS(Succ(Zero), Zero) → new_primDivNatS(new_primMinusNatS2, Zero)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
new_primDivNatS(Succ(Succ(vuy30000)), Zero) → new_primDivNatS(new_primMinusNatS1(vuy30000), Zero)
The TRS R consists of the following rules:
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
new_primMinusNatS2 → Zero
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS1(x0)
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [15,17,22] contains 2 SCCs with 1 less node.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS(Succ(Succ(vuy30000)), Zero) → new_primDivNatS(new_primMinusNatS1(vuy30000), Zero)
The TRS R consists of the following rules:
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
new_primMinusNatS2 → Zero
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS1(x0)
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [15] we can delete all non-usable rules [17] from R.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS(Succ(Succ(vuy30000)), Zero) → new_primDivNatS(new_primMinusNatS1(vuy30000), Zero)
The TRS R consists of the following rules:
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS1(x0)
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ RuleRemovalProof
↳ QDP
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS(Succ(Succ(vuy30000)), Zero) → new_primDivNatS(new_primMinusNatS1(vuy30000), Zero)
The TRS R consists of the following rules:
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
The set Q consists of the following terms:
new_primMinusNatS1(x0)
We have to consider all minimal (P,Q,R)-chains.
By using the rule removal processor [15] with the following polynomial ordering [25], at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented.
Strictly oriented dependency pairs:
new_primDivNatS(Succ(Succ(vuy30000)), Zero) → new_primDivNatS(new_primMinusNatS1(vuy30000), Zero)
Strictly oriented rules of the TRS R:
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
Used ordering: POLO with Polynomial interpretation [25]:
POL(Succ(x1)) = 1 + 2·x1
POL(Zero) = 0
POL(new_primDivNatS(x1, x2)) = x1 + x2
POL(new_primMinusNatS1(x1)) = 2 + 2·x1
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ RuleRemovalProof
↳ QDP
↳ PisEmptyProof
↳ QDP
↳ QDP
Q DP problem:
P is empty.
R is empty.
The set Q consists of the following terms:
new_primMinusNatS1(x0)
We have to consider all minimal (P,Q,R)-chains.
The TRS P is empty. Hence, there is no (P,Q,R) chain.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS1(vuy30000) → Succ(vuy30000)
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
new_primMinusNatS2 → Zero
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS1(x0)
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [15] we can delete all non-usable rules [17] from R.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS2
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS1(x0)
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.
new_primMinusNatS2
new_primMinusNatS1(x0)
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
By rewriting [15] the rule new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53)) at position [0] we obtained the following new rules:
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
By rewriting [15] the rule new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(Succ(vuy52), Succ(vuy53)), Succ(vuy53)) at position [0] we obtained the following new rules:
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
↳ QDPOrderProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
We use the reduction pair processor [15].
The following pairs can be oriented strictly and are deleted.
new_primDivNatS(Succ(Succ(vuy30000)), Succ(vuy31000)) → new_primDivNatS0(vuy30000, vuy31000, vuy30000, vuy31000)
The remaining pairs can at least be oriented weakly.
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
Used ordering: Polynomial interpretation [25]:
POL(Succ(x1)) = 1 + x1
POL(Zero) = 0
POL(new_primDivNatS(x1, x2)) = x1
POL(new_primDivNatS0(x1, x2, x3, x4)) = x1
POL(new_primDivNatS00(x1, x2)) = x1
POL(new_primMinusNatS0(x1, x2)) = x1
The following usable rules [17] were oriented:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
↳ QDPOrderProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Zero, Zero) → new_primDivNatS00(vuy52, vuy53)
new_primDivNatS00(vuy52, vuy53) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Zero) → new_primDivNatS(new_primMinusNatS0(vuy52, vuy53), Succ(vuy53))
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [15,17,22] contains 1 SCC with 3 less nodes.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
↳ QDPOrderProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
↳ UsableRulesProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
The TRS R consists of the following rules:
new_primMinusNatS0(Succ(vuy390), Succ(vuy400)) → new_primMinusNatS0(vuy390, vuy400)
new_primMinusNatS0(Zero, Succ(vuy400)) → Zero
new_primMinusNatS0(Zero, Zero) → Zero
new_primMinusNatS0(Succ(vuy390), Zero) → Succ(vuy390)
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [15] we can delete all non-usable rules [17] from R.
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
↳ QDPOrderProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
R is empty.
The set Q consists of the following terms:
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
We have to consider all minimal (P,Q,R)-chains.
We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.
new_primMinusNatS0(Succ(x0), Zero)
new_primMinusNatS0(Succ(x0), Succ(x1))
new_primMinusNatS0(Zero, Zero)
new_primMinusNatS0(Zero, Succ(x0))
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ DependencyGraphProof
↳ AND
↳ QDP
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ Rewriting
↳ QDP
↳ Rewriting
↳ QDP
↳ QDPOrderProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
↳ UsableRulesProof
↳ QDP
↳ QReductionProof
↳ QDP
↳ QDPSizeChangeProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the subterm criterion [20] together with the size-change analysis [32] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs:
- new_primDivNatS0(vuy52, vuy53, Succ(vuy540), Succ(vuy550)) → new_primDivNatS0(vuy52, vuy53, vuy540, vuy550)
The graph contains the following edges 1 >= 1, 2 >= 2, 3 > 3, 4 > 4
↳ HASKELL
↳ LR
↳ HASKELL
↳ IFR
↳ HASKELL
↳ BR
↳ HASKELL
↳ COR
↳ HASKELL
↳ LetRed
↳ HASKELL
↳ NumRed
↳ HASKELL
↳ Narrow
↳ AND
↳ QDP
↳ QDP
↳ QDP
↳ QDPSizeChangeProof
Q DP problem:
The TRS P consists of the following rules:
new_primMinusNat(vuy39, vuy40, Succ(vuy410), Succ(vuy420)) → new_primMinusNat(vuy39, vuy40, vuy410, vuy420)
R is empty.
Q is empty.
We have to consider all minimal (P,Q,R)-chains.
By using the subterm criterion [20] together with the size-change analysis [32] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs:
- new_primMinusNat(vuy39, vuy40, Succ(vuy410), Succ(vuy420)) → new_primMinusNat(vuy39, vuy40, vuy410, vuy420)
The graph contains the following edges 1 >= 1, 2 >= 2, 3 > 3, 4 > 4